Chemistry of Life

2

 

Chemistry of Life: pH and Buffers Student Name Date

Data

 

Activity 1

 

Calculate the volume of 1 M NaOH needed to prepare 10.0 mL of a 0.10 M solution.

 

Calculate the volume of 1 M HCl needed to prepare 10.0 mL of a 0.10 M solution.

 

Data Table 1

 

  Initial pH pH after 1 drop 0.1M HCl pH after 10 drops 0.1M HCl pH after 1 drop 0.1M NaOH pH after 10 drops 0.1M NaOH
Water          
pH 4 buffer          
pH 6 buffer          
pH 8 buffer          

 

 

 

In Activity 1, what happened to the pH of the water sample as 0.1 M HCl was added? How did this compare to what happened with addition of one drop of 0.1 M HCl to each buffer solution?

 

In Activity 1, why did the pH of the buffer solutions change after the addition of 10 drops of 0.1 M NaOH? Activity 2

 

Activity 2

Data Table 2

 

  Initial pH pH after 1 drop 0.1M NaOH pH after 2 drops 0.1M NaOH pH after 4 drops 0.1M NaOH pH after 8 drops 0.1M NaOH
100%          
50%          
25%          
12.5%          

 

 

In Activity 2, which concentration was the effective buffer? Explain what happened chemically as the buffer became more dilute.

 

Explain how the buffer could be diluted (in Activity 2), yet maintain the same pH. Hint: Reference the Henderson-Hasselbalch equation.

 

Photos

 

Photo 1

 

Insert photo of results of Activity 1.

 

The following should be visible in this photo:

· Row and column labels

 

 

Photo 2

 

Insert photo of results of Activity 2.

 

The following should be visible in this photo:

· Row and column labels

 

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Using Genetics To Treat Disease

* This case study presents a fictitious scenario, but one that is based upon clinical observations.

† Background information on Acute Lymphocytic (Lymphoblastic) Leukemia modified from Satake, N., Acute Lymphoblastic Leukemia, http://www.emedicine.com/ped/topic2587.htm. Last accessed: 07/08/09.

“Pharmacogenetics” by Jeanne Ting Chowning Page 1

by

Jeanne Ting Chowning Department of Education, Northwest Association for Biomedical Research

Part I – Acute Lymphocytic (Lymphoblastic) Leukemia It’s called the children’s ward. For two teenagers who have been recently diagnosed with leukemia, it seems insulting to have their lives hijacked by doctors and nurses with stuffed animals clipped to their stethoscopes.

Laura is a forward on her school soccer team and leads the league in scoring. For the last four months, she has been really tired, but nothing seemed really wrong until her legs became covered with bruises. Just pressing her fingers on her skin was practically enough to make a bruise. It didn’t seem real when her doctor, Jane Ryder, diagnosed her with Acute Lymphocytic (or Lymphoblastic) Leukemia (ALL), or when she told her that ALL is the most common malignant (spreading) cancer found in children. She’s 14 years old; she’s not a child!

Beth is 13 and looks remarkably like Laura. Both have straight dark hair, large brown eyes, and tall slender builds. Beth has never been that athletic; she prefers reading and theater. She’s hoping to be part of the drama team next year when she goes to high school, even though she’ll only be a freshman. But she’s been missing a lot of school because of one virus after another, lots of fevers and night sweats, then that rash in the fall. Now she’s in a hospital, and it seems like the only people she sees are her parents, Dr. Ryder, and the nurses.

Laura and Beth both have ALL, which arises from the uncontrolled growth of immature lymphocytes (a type of white blood cell, or leukocyte). These cells, which are “stuck” in an early stage of development, become so numerous that they crowd out normal blood cells. Each year about 30 cases occur per million people, and most of those cases are in children aged 2–5 years. The cause of ALL remains largely unknown, although a small number of cases are associated with inherited genetic syndromes.† Both girls are suffering from anemia (low blood cell levels), fevers, bleeding, and are pale and thin. Dr. Ryder has decided to treat them as in- patients, keeping them in the hospital while treating them with a “thiopurine” drug called 6-mercaptopurine (6-MP) known to be highly effective in treating leukemia. Thiopurines are very similar to the regular purine nitrogen bases such as adenine and guanine that make up DNA and RNA. The only difference is that thiopurines have an extra sulfur group attached to them. They are similar enough to a regular purine base that our cells convert them to nucleotides (with the addition of a deoxyribose sugar and phosphate). These modified thioguanine nucleotides (TGN) are then incorporated into DNA.

The TGN nucleotides interfere with DNA replication and stop rapidly growing cells like cancer cells from further growth. Unfortunately, they also block the growth of other fast growing cells needed for good health, like the cells in the bone marrow that develop into erythrocytes (red blood cells) and leukocytes. As with

Pharmacogenetics: Using Genetics to Treat Disease*

 

 

“Pharmacogenetics” by Jeanne Ting Chowning Page 2

many drugs given as chemotherapy, it is important to give a high enough dosage to prevent cancer cells from replicating, while avoiding damage to the normal tissues. Too high a drug dose can be very toxic. Dr. Ryder knows that drugs are processed in various ways in the body. They must be absorbed by the blood, distributed throughout the body’s tissues, converted or transformed into forms that are easier to eliminate, and then removed from the body. Dr. Ryder gives both girls the same dosage of the drug before leaving the hospital for the night.

While making her rounds over the next few days, Dr. Ryder sees Laura’s vital signs plummet. Her anemia has worsened; her erythrocyte count is so low that her heart function could be compromised. Her fevers are spiking, and her breathing is becoming shallow and labored. She is not eating and is being hydrated intravenously. Her condition is life-threatening. In contrast, Beth’s anemia has decreased, she is free of fever, and is actually showing signs of an appetite and boredom, good indicators of improved health. Dr. Ryder had not anticipated that the drug could act so differently in two individuals. Even as she looks at Beth’s chart, she can picture Laura’s body struggling to hold its own just two private rooms away. Dr. Ryder knows she must find out why her patients are responding so differently. But where should she start, and will she find an answer in time to help Laura?

Questions 1a. Suggest a reason why the drug might affect the two girls differently.

1b. What tests might Dr. Ryder order to determine why the two girls are reacting as they are to the drug? Provide two or three appropriate examples of tests.

 

 

“Pharmacogenetics” by Jeanne Ting Chowning Page 3

Part II – Enzyme Activity Dr. Ryder learns that the difference in patient reaction to the drug probably has something to do with how the drug is naturally metabolized in the body to be removed as waste. After searching the scientific literature, she learns that the drug 6-MP can either be converted to the active form, TGN nucleotides, or can be inactivated with the help of the TPMT enzyme (thiopurine methyltransferase). Within each patient who takes the drug, both processes are occurring and they compete with each other.

Figure 1. Flow Chart Flow chart showing activiation and inactivation paths of the drug 6-MP.

 

 

“Pharmacogenetics” by Jeanne Ting Chowning Page 4

Since the therapy aims to harm rapidly replicating cells without overly impacting normal ones, it is important that excess drug is inactivated. Dr. Ryder decides to see how levels of the TPMT enzyme activity might vary between people.

She reviews the research papers that have been published about the TPMT enzyme and finds an interesting graph. From a study of 298 randomly selected Caucasian individuals, researchers found the following levels of TPMT enzyme activity:

Figure 2. Simplified Results. Simplified bar graph showing results from a study of 298 randomly selected Caucasian patients.

Questions 2a. If Dr. Ryder had 10 Caucasian patients in the next month, how many would you predict to have each

of the TPMT enzyme activity levels, based on the graph above?

Low:

Medium:

High:

Would you expect the actual/observed number of patients to be different? Why might there be differences?

2b. Each individual inherits two copies of the gene for the enzyme, one from each parent. Dr. Ryder suspects that variation in enzyme activity level is controlled by two different versions (alleles) of that gene. Does this graph (and the number of phenotypes) suggest that enzyme activity levels are based on a dominant/recessive or a codominant pattern of inheritance? Explain your answer.

Source: Simplified graph patterned after the top panel of Figure 2 in: Weinshilboum, R.M., and S. Sladek (1980) Mercaptopurine pharmacogenetics: Monogenic inheritance of erythrocyte thiopurine methyltransferase activity. American Journal of Human Genetics 32:651–662.

 

 

“Pharmacogenetics” by Jeanne Ting Chowning Page 5

2c. Which bar (low, medium, or high) represents individuals who might be homozygous for a “low enzyme activity’” version of the gene? Which bar represents individuals who might be homozygous for a “high enzyme activity” version of the gene? Which bar represents heterozygotes?

2d. Answer the question: “How does enzyme activity level vary among the patients examined?” In your answer, be sure to include supporting data from the graph above. Explain how these data support your conclusion.

2e. Challenge question: The actual graph (below) showed much more detail. Why do you think that there is more variation between patients than shown in the simplified graph?

Figure 3. Histogram RBC TPMT frequency distribution histogram for 298 randomly selected Caucasian subjects.

Source: Histogram drawn after top panel of Figure 2 in: Weinshilboum, R.M., and S. Sladek (1980) Mercaptopurine pharmacogenetics: Monogenic inheritance of erythrocyte thiopurine methyltransferase activity. American Journal of Human Genetics 32:651–662.

 

 

“Pharmacogenetics” by Jeanne Ting Chowning Page 6

Part III – TPMT Enzyme Activity Levels Dr. Ryder tested Laura, who was very sick, and found that her TPMT enzyme activity level was extremely low.

Question 3a. Why would individuals with the lowest level of enzyme get the sickest when they take the drug?

Suggest one possible reason.

Investigating further, Dr. Ryder decides to look at drug levels in many patients who are all receiving the same standard doses of the thiopurine drug and compare them to enzyme levels. When she compares the level of thioguanine nucleotides (TGN) created by the thiopurine drug to the body’s level of TPMT enzyme in patients, this is what she finds:

Figure 4. Scatter Plot of TGN vs. Enzyme Activity Thioguanine nucleotide concentrations and TPMT enzyme activity levels in 95 Children with Acute Lymphoblastic Leukemia (ALL) who were being treated with standard doses of thiopurine drugs.

Source: Modified from Lennard L., J.S. Lilleyman, J. Van Loon, and R.M. Weinshilboum (1990) Genetic variation in response to 6-mercaptopurine for childhood acute lymphoblastic leukaemia. Lancet 336:225–229.

Question 3b. Describe the relationship between TPMT enzyme activity levels and TGN levels. Be sure to include

supporting data from the graph.

 

 

“Pharmacogenetics” by Jeanne Ting Chowning Page 7

Part IV – Putting It All Together From her research, Dr. Ryder hypothesized that patients such as Laura (who became very sick upon receiving the drug) have very high / low TPMT enzyme activity and therefore very high / low levels of TGN nucleotides at normal doses. They easily became sick from the effects of the drug, and could even die. These patients are homozygous / heterozygous for the version of the gene encoding high / low enzyme activity. A better drug dose for these patients is 1/10th the level of other patients.

Patients such as Beth with high / low TPMT enzyme activity had high / low levels of TGN nucleotides. These patients would do well with the drug, and in some cases might even need a larger-than-normal dosage for the treatment to be most effective. These patients were either homozygous for the version of the gene encoding high / low enzyme activity, or were heterozygous.

Based on the graph in Part II, about 10% of the Caucasian population is homozygous / heterozygous.

Question 4. In the paragraphs above, circle the correct answer (high or low, heterozygous or homozygous).

 

 

“Pharmacogenetics” by Jeanne Ting Chowning Page 8

Part V – SNPs and TPMT DNA techniques reveal TPMT gene is located on chromosome 6, is about 34 kilobases in length (34,000 DNA bases), and has 8 exons. An exon is a region of a gene that is present in the final functional transcript (mRNA) from that gene. The diagram below shows a representation of the TPMT gene, showing the exons as boxes. The first “wild type” is the most common version. In our case, the second version of the TPMT gene is associated with low enzyme activity (TPMT*3A) and has two single nucleotide polymorphisms (SNPs), or changes in single DNA nucleotide bases (from “G” to “A” in one case and from “A” to “G” in another) that result in different amino acids being inserted in the enzyme. This, in turn, affects the enzyme’s function. Over 20 different gene variants have been found, three of which are shown below.

Figure 5. Selected Human TPMT Alleles. The wild-type human TPMT allele (TPMT*1) and variant alleles TPMT*3A, TPMT*3B, and TPMT*3C. Rectangles represent exons, with black coding areas and white untranslated regions.

Source: Weinshilboum, R. (2001) Thiopurine pharmacogenetics: Clinical and molecular studies of Thiopurine Methyltransferase, American Society for Pharmacology and Experimental Therapeutics 29:601–605. Available online at http://dmd.aspetjournals.org/. This case is based on this article.

Questions 5a. Dr. Ryder now has the ability to conduct a SNP genetic test on her patients to determine what level

of drug they should get. A new patient on the ward, Kevin, is homozygous for TPMT 3A*. The graph shown in Part III is reproduced on the next page. Circle the area of the graph that might likely corresponds to Kevin’s TGN and enzyme activity levels. Explain why you circled that region.

 

 

“Pharmacogenetics” by Jeanne Ting Chowning Page 9

Case copyright held by the National Center for Case Study Teaching in Science, University at Buffalo, State University of New York. Originally published February 4, 2010. Please see our usage guidelines, which outline our policy concerning permissible reproduction of this work. Title block illustration, licensed, ©Scott Maxwell | Dreamstime.com.

5b. What level of the drug (low, medium, or high) should Dr. Ryder give him? Explain your answer.

5c. In your own words, summarize how knowing someone’s TPMT DNA sequence could be used to determine what kind of medical care they should receive.

Postscript Dr. Ryder responded quickly to Laura’s drug reaction. She discontinued the drug while alternate treatment regimens were explored, and Laura’s condition began to improve.

 

 
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Cell Cycle

DATE___________________

Chapter 12- Cell Cycle

1. Phases of the cell cycle– An organism’s body cells have 4 chromosomes.

A. Identify the major characteristics of each phase.

B. OPTIONAL Draw a picture to illustrate these characteristics.

Cell Cycle Phase A. Characteristics of phase B. OPTIONAL-Illustration of phase
Interphase G1-

S-

G2-

 

Prophase  

 

Metaphase  

 

Anaphase  

 

Telophase  

 

Cytokinesis  

 

-A researcher treats cells with a chemical that prevents DNA synthesis. This treatment traps the cells in which part of the cell cycle?

#2 OPTIONAL PRACTICE

2. Phases of the cell cycle– An organism’s body cells have 2 chromosomes

A. Identify the major characteristics of each phase.

B. Draw a picture to illustrate these characteristics.

Cell Cycle Phase A. Characteristics of phase B. Illustration of phase
Interphase G1-

S-

G2-

 

Prophase  

 

Metaphase  

 

Anaphase  

 

Telophase  

 

Cytokinesis  

 

3. During anaphase, do kinetochore microtubules:

Hypothesis #1: shorten at their spindle pole ends?

Hypothesis #2: shorten at their kinetochore ends?

EXPERIMENTAL RESULT:

image1.png

-CONCLUSION:

-What observation would have to have been made to support the OTHER hypothesis?

4A. Cyclin combines with Cyclin Dependent Kinase (CdK) to form Maturation Promoting Factor (MPF). The Cyclin concentration and MPF activity during the cell cycle are shown in the figure below. Describe where a line on the graph would be drawn to represent the CdK concentration through the cell cycle.

image2.png

B. Using your understanding of the molecules that control the G2 checkpoint and the graph above, make at least one statement about when these molecules are present & absent during the cell cycle and how this results in cell cycle control.

5. Tumors

  Benign Malignant Metastatic
Describe basic structure of this tumor.      
Cancerous cells?      
Localized to single tissue/organ?      
Prognosis (good/fair/poor)      
Typical treatment?      

Chapter 13-Meiosis and Sexual Life Cycles

1. Important Terminology: Match the terms listed below with the appropriate letter in the figure below.

Sister chromatids

Nonsister chromatids

Homologous pair

Centromere

 

image3.emfCopyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings

ABCD

 

2. Describe the differences between the somatic cell s and gametes in your body.

  Somatic cell Gamete
Number of chromosomes    
Ploidy (haploid or diploid)    
Example    

3. Phases of Meiosis– An organism’s body cells have 4 chromosomes (2 pairs)

A. Identify the major characteristics of each phase that differs from Mitosis.

B. OPTIONAL Draw a picture to illustrate these characteristics.

Meiosis Phase A. Characteristics of phase that differs from Mitosis B. OPTIONAL-Illustration of phase
Interphase  

 

Prophase I  

 

Metaphase I  

 

Anaphase I  

 

Telophase I & cytokinesis  

 

Prophase II  

 

Metaphase II  

 

Anaphase II  

 

Telophase II & cytokinesis  

 

#4 OPTIONAL PRACTICE

4. Phases of Meiosis– An organism’s body cells have 2 chromosomes (1 pair)

A. Identify the major characteristics of each phase that differs from Mitosis.

B. Draw a picture to illustrate these characteristics.

Meiosis Phase A. Characteristics of phase that differs from Mitosis B. Illustration of phase
Interphase  

 

Prophase I  

 

Metaphase I  

 

Anaphase I  

 

Telophase I & cytokinesis  

 

Prophase II  

 

Metaphase II  

 

Anaphase II  

 

Telophase II & cytokinesis  

 

5. Fruit flies have a diploid number of 8, and honeybees have a diploid number of 32. Assuming no crossing over, is the genetic variation among offspring from the same two parents likely to be greater in fruit flies or honeybees? Explain.

Chapter 14-Mendel and the Gene Idea

1. Genetics Terminology

Match each commonly used genetics term with its appropriate definition or example.

TERMS: DEFINITIONS AND EXAMPLES:

​__ heterozygous a. Blue-eyed blonde mates with brown-eyed brunette

__ homozygous b. BB or bb

__ monohybrid cross c. not on sex chromosomes

__ autosomal d. blue or brown eyes

__ genotype e. Bb

___ phenotype f. locus on a chromosome that codes for a given polypeptide

__ gene g. Blonde mates with brunette.

__ allele h. BBBb, or bb

__ dihybrid cross i. Males have only one for each gene on the X chromosome

2. Make a punnett square using the following information.

Traits: Oval eyes = A, Round eyes = a

Parents: Mom Aa, Dad aa

-What eye shape does Mom have?

-What eye shape does Dad have?

-What fraction of the offspring will have oval eyes?

-What fraction of the offspring will have round eyes?

-What fraction of the offspring will have the Homozygous Dominant genotype AA?

-What fraction of the offspring will have the Heterozygous genotype Aa?

-What fraction of the offspring will have the Homozygous Recessive genotype aa?

3. Make a punnett square using the following information.

Traits: Brown eyes = B, Blue eyes = b

Parents: Mom Bb, Dad Bb

-What eye color does Mom have?

-What eye color does Dad have?

-What fraction of the offspring will have brown eyes?

-What fraction of the offspring will have blue eyes?

-What fraction of the offspring will have the Homozygous Dominant genotype BB?

-What fraction of the offspring will have the Heterozygous genotype Bb?

-What fraction of the offspring will have the Homozygous Recessive genotype bb?

4. Multi-hybrid cross #1:

3 characters = trihybrid cross

Parent 1: Purple flowers (Pp), Yellow (Yy), Round (Rr)

Parent 2: Purple flowers (Pp), green (yy), wrinkled (rr)

Parents: PpYyRr X Ppyyrr

Question: What percentage of the offspring from this cross would be predicted to have the following genotypes: Ppyyrr, PPyyrr

1. Consider each character separately (make a punnett square for each character)

Parents: PpYyRr X Ppyyrr:

Pp X Pp =

Yy X yy =

Rr X rr =

2. Calculate probability for each genotype using the Rule of Multiplication

Ppyyrr ½ x ½ x ½ = 2/16

PPyyrr

3. Use the Rule of Addition to determine the probability of offspring that have the following genotypes:

Ppyyrr =2/16

PPyyrr =

5. Multi-hybrid Cross #2

3 characters = trihybrid cross

Parent 1: White flowers (pp), Yellow (Yy), Wrinkled (rr)

Parent 2: Purple flowers (Pp), Green (yy), Round (Rr)

Parents : ppYyrr X PpyyRr

Question: What percentage of the offspring from this cross would be predicted to have the following genotypes: ppyyrr (phenotype: white flowers and green and wrinkled seeds)?

1. Consider each character separately (make a punnett square for each character)

Parents: ppYyrr X PpyyRr:

pp X Pp =

Yy X yy =

rr X Rr =

2. Calculate probability for the genotype using the Rule of Multiplication

ppyyrr=

3. Use the Rule of Addition to determine the probability of offspring that have the genotype ppyyrr (phenotype: white flowers and green and wrinkled seeds)?

6. Pedigree for a recessive trait . Determine the genotype and phenotype of each individual in the pedigree shown below. Use A for dominant, a for recessive.

image4.png

7. Joan was born with six toes on each foot, a dominant trait called polydactyly. Two of her five siblings and her mother, but not her father, also have extra digits. Draw a pedigree inclucing all family members mentioned in the question. Use D and d to symboloze the alleles for this character. What is Joan’s genotype for the “number-of-digits” character?

Chapter 15-The Chromosomal Basis of Inheritance

1. A heterozygous brown-eyed human female who is a carrier of color blindness marries a blue-eyed male who is not color-blind. Color blindness is a sex-linked trait. Assume that eye color is an autosomal trait and that brown is dominant over blue. What is the probability that any of the offspring produced have the traits listed? Construct two punnett squares, one for hair color and one for color blindness.

Eye color (autosomal trait):

  B b
b    
b    

Color blindness (sex-linked trait):

  XA Xa
XA    
Y    

a. Brown eyes

b. Blue eyes

c. Color blind OFFSPRING?

d. What fraction of the MALE OFFSPRING will be color-blind?

e. What fraction of the FEMALE OFFSPRING will be color-blind?

f. What fraction of the FEMALE OFFSPRING will be carriers for colorblindness?

g. What fraction of the MALE OFFSPRING will be carriers for colorblindness?

h. What fraction of the TOTAL OFFSPRING will have Brown-eyes and be color-blind?

i. Why do males show sex-linked traits more often than females?

2A. Describe the process of X inactivation in female mammal body cells.

2B. Why does this process not occur in male mammal body cells?

2C. Discuss at least one possible reason for this phenomenon.

3. Construct a linkage map using the following gene recombination frequencies.

The Recombination Frequency between characters:

A and B = 30%, A and C = 20%, and B and C = 10%.

4. Rip two long strips of paper from a piece of scrap paper. On the end of each strip of paper write “A B C D”. These letters represent gene alleles on non-sister chromosomes that are crossing over during prophase I of meiosis. Rip one strip between the B and C and Rip the other strip between the C and D. Transfer the pieces you ripped off to the other non-sister. Record the sequence of alleles on each non-sister below.

Sequence on non-sister 1:

Sequence on non-sister 2:

-What type of chromosome alterations have occurred?

PAGE

16

 

 

 

A

 

 

 

B

C

 

 

D

 

Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings

 
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Applied Human Genetics

Lab 5: Follow the instructions and complete the assignment below. Submit your answers through the Lab 5 Assignment on Blackboard.

Lab 5 1

Lab 5: Solvents and cells

Part 1: Chemistry of Molecules Read/watch the provided resources and take notes, applying the information to what we learned this week. CO2 and Soda: https://www.youtube.com/watch?v=HFCeV5BVBh0 Dissolving M&Ms: https://www.youtube.com/watch?v=umJmRaG6v80 When you are finished, answer the following questions: 1. You are having a debate with a friend about the science behind the Diet Coke and Mentos phenomenon. Your friend thinks that since the volume of matter after the experiment (the big mess) seems to be more than what was originally present in the individual components (soda/Mentos) before they were combined, that the “explosion” is the result of carbon dioxide being produced (made) by the reaction. Is this true? Does the amount of carbon dioxide increase through this reaction? Use what you’ve learned this week to verify or debunk your friend’s argument.

2. During the M&Ms experiment, why did the scientist emphasize that each of the treatments in this experiment needed to be stirred the same say, for the same length of time?

3. For the M&M experiment, name and describe the chemical property that is demonstrated by both the sugar and the candy coloring in the shell of an M&M that permits dissolution in the water, but not in the oil.

4. In your own words discuss this quote. Was Jamf mistaken in his understanding of the relative strengths of ionic and covalent bonds? Explain why/why not (in your own words!).

 

5. The scientific field of organic chemistry is based entirely on studying the chemical structure and reactivity (bonds and chemical reactions) of carbon containing molecules. Based on what you learned in class this week, discuss why carbon is so important that entire fields of study are dedicated to understanding and applying it.

 

 

 

 

Lab 5: Follow the instructions and complete the assignment below. Submit your answers through the Lab 5 Assignment on Blackboard.

Lab 5 2

Part 2: A Picture is Worth a Thousand Words This unit we learned about cells, their structure, and how they carry out the processes of life. We know that there are size restrictions that prevent living cells from being too small or too large. However, the rules that govern cell size may be more complex than scientists originally thought. The existence of ultra-small living cells has been debated for two decades. This debate was settled in February of 2015, when researchers from the U.S. Department of Energy’s National Laboratory at UC Berkeley obtained the first microscopy images of ultra-small bacteria- about as small as life can get. Follow this youtube link to view the research images/reconstructed videos of the cell structure: https://www.youtube.com/watch?v=ofNrtg-FpSc; primary article may be provided upon request. This part of the lab will focus on a popular media ScienceDaily article that summarizes the researchers’ findings. However, before we investigate these ultra-small nanobes, it is important that we fully comprehend the history and scientific impact behind this debate. For this, you’ll need to read the following extract: “In 1996, researchers published a description of a meteorite that fell from Mars, which sparked a long and complicated debate over the existence of what they called ‘nanobacteria’, later also described as nanobes. Various teams argued over whether life, theoretically, could live to be that size, but the debate didn’t really get anywhere because no one really had any evidence for either side. One side said all the things needed for life – DNA, RNA, proteins and solvents – couldn’t actually fit inside a cell that small, while others said life could be that small, but just in a starved, inactive state. Researchers argued over the theoretical limit for how small a cell could get in diameter and volume, and one team even reported finding some marine nanobes, but lacked direct microscopic evidence to prove they fit inside the size range to classify them as such. But now, such bacteria found in some Colorado groundwater have been imaged, and these things are undeniably tiny – several times tinier than several estimates for the lower size limit of life on Earth, in fact. And as difficult as it is to see them, the researchers think they could actually be quite common.” http://www.sciencealert.com/new-images-reveal-the-tiniest-known-life-forms-on-earth Next, click the link to read the article describing researchers’ findings and use this information, along with what you learned this week to answer the provided questions. https://www.sciencedaily.com/releases/2015/02/150227181339.htm When you are finished, answer the following questions: 6. The image at the beginning of the ScienceDaily article shows and describes the visible structure of the cell, and the authors state: “The cell has a very dense interior compartment and a complex cell wall.” As you remember from your readings, not all cell types contain a cell wall. What kinds of cells, other than bacteria, would you expect to possess a cell wall? List the

 

 

Lab 5: Follow the instructions and complete the assignment below. Submit your answers through the Lab 5 Assignment on Blackboard.

Lab 5 3

functions that this structure provides for these organisms. How do organisms that don’t have a cell wall execute these same functions? 7. The image at the beginning of the ScienceDaily article shows and describes the visible structure of the cell, and the authors state: “The darker spots at each end of the cell are most likely ribosomes.” Of all the different structures that could exist within a cell, why do you think that the authors think that these are ribosomes? (Hint: think about the types of cellular structures that are/aren’t found within bacteria, and what ribosomes do, and the importance of that job, within a cell.)

8. Interestingly, the ScienceDaily article states: “images also revealed dividing cells, indicating the bacteria were healthy and not starved to an abnormally small size.” This statement implies that in order for cells to divide they must be “healthy”. Discuss the requirements that a “healthy” eukaryotic cell must meet before it will under cell division. What are the consequences if a eukaryotic cell divides even if these requirements are not met? 9. The ScienceDaily authors state: “About 150 of these bacteria could fit inside an Escherichia coli cell and more than 150,000 cells could fit onto the tip of a human hair”. To provide you with some context so that you can really understand this statement: the spherical diameter of a

typical Escherichia coli cell is 1.3 m (micrometers), and the spherical diameter of these new

ultra-small bacteria is ~0.23 m. Compare the SVR of these new ultra-small bacteria to that of a typical E. coli cell (Hint: you need to calculate the SVR for each), which organism has a larger SVR, does this make sense in the context of the size of the cell? 10. Throughout the ScienceDaily article, the researchers studying these tiny bacteria acknowledge the challenges that such small cells face when it comes to performing the basic functions of life, and the additional challenges that limit our ability to study such small organisms. This makes sense, considering that previously calculated theoretical minimum diameter of a cell was established (and generally accepted by respected scientists and experts

in the field) to be 0.250-0.30 m. The authors say, “There isn’t a consensus over how small a free-living organism can be, and what the space optimization strategies may be for a cell at the lower size limit for life.” Why, before this, did scientists think that living cells couldn’t be much smaller than this lower limit (why is it that when a cell is too small, that it “can’t” survive)?

11. Choose another statement/quote from this article (or the other summary or the original research paper) and discuss how it relates to the material that we learned this week. Be sure to use specific examples (and your own words).

 
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